0.75p^2-70p-500=0

Solution for 0.75p^2-70p-500=0 equation:

0.75p^2-70p-500=0

a = 0.75; b = -70; c = -500;
Δ = b2-4ac
Δ = -702-4·0.75·(-500)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-80}{2*0.75}=\frac{-10}{1.5}
=-6+1/1.5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+80}{2*0.75}=\frac{150}{1.5}
=100
$